Biology 1001A Lecture Notes - Lecture 20: Inbreeding, Heterozygote Advantage, Allele Frequency
Use HW principle to infer evolutionary mechanisms.
1.) In a pond of 100 fish: 16 are black (genotype BB), 48 are gray (Bb) and 36 are white (bb), what can
you reasonably conclude about selection at this locus?
A. Selection probably favours b allele
B. Selection probably favours heterozygotes
C. Selection is probably not occurring
Is population in HWE? p = 0.4, q = 0.6 (0.42 = expeted geotpe feue of BB…)
Observed and Expected correspond so population is in HWE, so selection is not occurring
2.) In a flock of 100 birds, 5 have red feathers (Genotype RR), 90 have purple feathers, (Rr) and 5 have
blue feathers (rr). Which of the following is most likely?
A. f(r)= f(R), so selection is not operating on feather colour (red herring, just because allele
frequencies are equal to 0.5 and 0.5 does not mean selection is not occurring this situation
ould ou i heteozgote adatage (o dissoiatie atig fo feathe olou ut e do’t
worry about that b/c it is not selection), the only way to see if selection is not happening is to
see if the population is in HWE or not. (Selection acts on phenotypes, not genotypes/alleles!)
B. The population is extremely inbred
C. selection at this locus favours heterozygotes
Population is not in HWE and there are much more observed heterozygotes than expected so
heterozygote advantage is most likely happening
3.) In a cave of 100 bats, 81 have long claws (CC) 18 have short claws (Cc) and one has no claws (cc).
Which explanation is most likely?
A. The bat without claws is a mutant
B. The bat without claws has immigrated from another population
C. Long-clawed bats have the highest relative fitness (seletio is’t happeig eause pop. is i
HWE)
D. All genotypes have equal relative fitness (If the hae the sae elatie fitess should’t the
number of individuals with each genotype be the same? No! because expected genotype
frequencies - number of individuals with each genotype - depends on the allele frequencies of
original population, not the relative fitness of the genotype) (i.e. just because a population has
an equal relative fitness does not mean that each genotype/phenotype occurs in the same
number of individuals)
Population is in HWE. (selection is not happening, so all genotypes have equal relative fitness).
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Document Summary
P = 0. 4, q = 0. 6 (0. 42 = expe(cid:272)ted ge(cid:374)ot(cid:455)pe f(cid:396)e(cid:395)ue(cid:374)(cid:272)(cid:455) of bb ) Observed and expected correspond so population is in hwe, so selection is not occurring. In a flock of 100 birds, 5 have red feathers (genotype rr), 90 have purple feathers, (rr) and 5 have blue feathers (rr). Population is not in hwe and there are much more observed heterozygotes than expected so heterozygote advantage is most likely happening. In a cave of 100 bats, 81 have long claws (cc) 18 have short claws (cc) and one has no claws (cc). Which explanation is most likely: the bat without claws is a mutant, the bat without claws has immigrated from another population, long-clawed bats have the highest relative fitness (sele(cid:272)tio(cid:374) is(cid:374)"t happe(cid:374)i(cid:374)g (cid:271)e(cid:272)ause pop. is i(cid:374) Population is in hwe. (selection is not happening, so all genotypes have equal relative fitness).