Applied Mathematics 2270A/B Lecture Notes - Lecture 5: Exact Differential, Integrating Factor

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Start with a solution, then work backwors to find a de. Then put the solution into the de and say you"ve solved a de lol. Partial derivatives these de are called exact de and have a solution of f(x,y) =c. So, i get a de of the form m(x,y)dx + n(x,y)dy = 0. "if it"s exact, all i have to find that function f at the start becuase m and n are partial derivatives of the function f in terms of x and y respectively" M is all the stuff in from of the dx. N is all the stuff in front of the dy. Example 2 (x+y) (x-y) dx + x (x-2y) dy = 0. Therefore since they"re not equal, they"re not exact. We now have to check to see if it"s 1st order linear or seperable to solve it. Example 3 (2x sin(y) - y sin(x)) + (x2 cos(y) +cos(x)) .

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