HMB265H1 Lecture Notes - Lecture 9: Centimorgan, Genetic Linkage, Genetic Distance

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12 May 2015
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HMB265H1 Full Course Notes
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HMB265H1 Full Course Notes
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Lecture 9 : linkage mapping. Genes on the same chromosome are linked, generate excess of parental. Gametes generates excess of parental gametes. With linkage: f1 hybrid makes gametes, and recombinant progeny"s are less than half. Sturtevant defined one genetic map unit (m. u. ) as the distance between genes for which 1 product of meiosis in. Case: - parent: red eyes and cut edges, and vermillion eyes and uncut edges. 13. 2% recombinance v and ct are 13. 2 map unites (m. u. ) away = 13. 2 centimorgans (cm) Or even which specific chromosome they are on. Assortment if genes are far apart = 50% recombinant. But if you get 2 crossovers, the alleles will swap and swap back up and get parental types again. The further 2 genes are, the most likely a double crossover event. Why a deficit of crossovers: random chance do statistical test (ex. Chi test: presence of one crossover in region reduces chance of adjacent crossover = interference = non- independent.

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