HMB265H1 Lecture Notes - Lecture 6: Wild Type, Dihybrid Cross, Caveolin 1

22 views3 pages

burgundymule401

31 Jan 2018

School

UTSG

Department

Human Biology

Course

HMB265H1

Professor

Maria Papaconstantinou

For unlimited access to Class Notes, a Class+ subscription is required.

avalack09 and 39844 others unlocked

HMB265H1 Full Course Notes

Verified Note

25 documents

Document Summary

These fish descended from an anscenter that could see. Over many years they got mutations that made them blind. When they crossed frish from the 1st cave tgether, all the f1 were blind because the 2 parents carried mutations in the same gene. When cav1 and 2 were crossed, the f1 can now see. The same happened for cave 1 and 3. Cave 1, 2 and 3 fish had mutations in different genes, but all these genes played roles in eye development. These 3 fish converged upon the same outward appearance, but they used different genes to do this. The deficiencies in 1 lineage were compensated for in another lineage. The phenotypes of the mutants would be the same. The wild type allele coplements the mutant allele. They are all mutant allales of the same gene. At the phenotypic level, the individual appears homozygpus. We want to isolate genes that play a role in tomatoe colour.

Related Questions

Pure-breeding strains of two mutant panthers were developed in different zoos. Neither mutant makes hair pigment, so the hair is transparent and the fur appears to be pink rather than the normal black. When each mutant was crossed to homozygous black panthers, the F1 were always black no matter which parent was pink. The mutants were called pink-1 (pk-1) and pink-2 (pk-2) for convenience, but it was not known whether they were mutations of the same gene or mutations in different genes.

C: What would be the result of a cross between pink-1 and pink-2 if the two mutations were in different genes? Include the genotypes of the panthers in your answe

D: What phenotypic ratio would occur in the F2 generation if the two mutations were in different genes

1a. For example you mate an orange eye fly mutant with a white eye fly mutant and you get all wild type offspring. Do the results from the cross indicate that the mutations for OE and WE are on the same gene or different genes?

1b. A cross between white eye fly mutant and wild type occurs. A male and female are selected from the F1 generation to mate to create F2 generation. In F2 generation: 75% are wild type and 25% are white eye. Do these findings support the answer from 1a? Why or why not?

orangehound825

PoB researcher Zhongshan has 10 yeast mutants that he isolated by mutangenizing yeast. None of them can grow on minimal media alone, or on minimal media (MM) supplemented with ornithine (Orn). He also finds that all of these mutants can grow on citrulline (Cit) or arginine (Arg). He wants to check if these mutants are "allelic", (i.e. the hypothesis that they affect the same gene), or if any are non-allelic (i.e. the hypothesis that they affect different genes). Which of the following would provide the best test of these alternative hypotheses?

Test if the mutants can grow when both Cit and Orn are added to MM.

Test if the mutants synthesize Arg or not when grown in the presence of Orn.

Do pairwise crosses of the mutants to see if their diploid progeny (i.e. daughter cells with a copy of every gene from one mutant parent plus a copy of every gene from the other mutant parent) can grow on MM supplemented with Cit or not.

Do pairwise crosses of the mutants to see if their diploid progeny can grow on MM supplemented with Orn or not.

None of the above experiments will be able to distinguish between allelism or non-allelism.

ultramarineclam721

HMB265H1 Lecture Notes - Lecture 6: Wild Type, Dihybrid Cross, Caveolin 1

HMB265H1 Full Course Notes

Document Summary

Get access

Related Documents

HMB265H1 Lecture Notes - Lecture 6: Dihybrid Cross, Zygosity, Phenotype

HMB265H1 Lecture Notes - Lecture 6: Wild Type, The Leaves, Base Pair

HMB265H1 Lecture Notes - Lecture 7: Mendelian Inheritance, Wild Type, Haploinsufficiency

Related Questions