What is the oxidation state assigned to Mn in potassium permanganate, KMnO4? (Recall that answers must be numbers, that is, F is -1 not 1- in HF.)
Answer:
CHM135H1 Lecture Notes - Lecture 33: Stoichiometry
90
CHM135H1 Full Course Notes
Verified Note
90 documents
Document Summary
Chm135h1 f - lecture 33 - chapter 18 (3) Balancing oxidation-reduction reactions by the half-reaction method in acidic solution. Balance o using h 2o :lots of water present. Balance h using h + : excess protons present in acidic solution. If necessary, multiply the half-reactions to equalize the number of electrons transferred. Check to ensure elements and charges are balanced. Assign oxidation states and determine the elements that are oxidized and reduced. 1(aq) + fe+2 (aq) fe+3(aq) + mn+2 (aq) First balance all the elements besides h and o. In acid solution, add h 2o to side that is o deficient; add h +1 to side that is h deficient, then balance o first, then h. Add number of electrons transferred to product side for oxidation, and to reactant side for reduction = balance charge. Multiply the half-reactions by factors so the electrons lost in oxidation equals the electrons gained in reduction.