CSCA48H3 Lecture Notes - Lecture 1: Asteroid Family, Product Rule
17 Aug 2017
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In lecture we introduced the topic of arrangement with repetition by counting how many different. 20-nucleotide molecules could give rise to the c-enzyme fragmentation: Ac, ac, aaatc, c, c, c, tata, tggc (a) although it seems we must consider all possible arrangements of 8 fragments when counting, we actually need only consider arrangements of 7 of the fragments. We then placed the 2 ac fragments, followed by the aaatc fragment and then the tggc fragment. Show that the same count is obtained by placing the fragments in different ways (e. g. , place the ac fragments first). Ac (7c2), c (5c3), aaatc (2c1), tggc (1c1) This shows that the same count is obtained by placing the fragments in different ways. How many different ways are there to place fragments: There are 4 possible fragments, and must calculate the number of ways to arrange 4 : = 24 different ways: given n objects, with r1 of type 1, r2 of type 2, .
