CHM110H5 Lecture Notes - Lecture 30: Titration, Acid Strength, Sodium Hydroxide
Document Summary
Have to circle question that you don"t want counted. 160 for 8 questions, 180 for all 9. If you don"t get the question in 20 minutes then move on to next question. Xe/xw = ne/nw = 0. 05/0. 95 = 1/19 nw = 19ne. Remember this ^ o o o o ne = nw/19 = 55. 5/19 = 2. 92 mol. Find m (mole/lsolution) d = 0. 997 g/ml --> 977g/lsolution. 977g = masse + massw = 46ne + 18nw = 46ne + 18(19ne) ne = 2. 57. Hcl/36. 5g hcl) = 11. 5m (35g hcl/100g sol)(1. 20g sol/ml sol)(1000ml/l sol)(1 mol (11. 5mol hcl/l sol) = (x mol hcl/0. 175 l sol) X = 2. 012 mol, [hcl] = 2 m. Koh + hcl --> k+ + cl- + h2o. K2co3 + 2 hcl --> 2k+ + 2cl- + co2 + h2o. Kcl = 100 - (56. 1 + 27. 6) = 16. 3% Molecules occupy volume which is not negligible as compared to the volume of the container, v.
