ADM 2304 Lecture Notes - Lecture 3: N100, Sampling Distribution, Standard Deviation
13 May 2017
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Binomial: mean = np sd = sqrt (npq) Test assumptions: np = n(1-p) = 100*. 5 = 50. Mean of sampling distribution, it follows normal distribution p. >p^ = sample pop sd of p^ = p. > if n is large enough that is np > 10 and n(1-p)>10. >with a large enough sample size, the sample proportion is an unbiased estimate of the true population proportion with low variability. A tv game show auditions potential contestants by giving them a general knowledge quiz consisting of 100 multiple choice questions (each with 5 possible answers). You pass the audition if you get 30% correct. Let x = # of correct answers n = 100 p = 1/5 or 0. 2 (probability of a correct answer) Chapter 2: estimation using con dence intervals estimated by x p estimated by p. 2 e. g, gallup polls the poll is accurate within 2 percentage points, 19 times out of 20 (95%) .
