PHYS 1300 Lecture Notes - Lecture 8: Projectile Motion
2 Nov 2017
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Phys 1300 - lecture 8 - two-dimensional kinematics. Examples of constant acceleration problems: projectile motion. As before, when acceleration is constant: aavg = ainst = acceleration. This leads to a = (v v0)/t and all other equations for constant acceleration. But there are vector expressions now: with constant acceleration only in the y-direction (ax = 0) projectile motion. In vertical direction, the object accelerates due to the force of gravity. Horizontal velocity is constant (ax = 0) At the top of the path, vertical velocity component is zero (vy = 0) **these features are only true with no air resistance: taylor swift jumps swiftly with a horizontal velocity of 12 m/s ad lands on the ground 22m below, how long is she in the air for? x-direction y-direction. Y = vy0t + ayt2 vx0 = 12 m/s vy0 = 0 m/s. 22 = (0)t + (-9. 8)t2 vx = 12 m/s vy = ? m/s.
