CHEM 1050 Lecture Notes - Lecture 17: Oxidation State, Bayerischer Rundfunk, Indium

• School: University of Guelph
• Department: Chemistry
• Course: CHEM 1050
• Professor: Mario Monteiro

Document Summary

Homework: 19. 35 a) + b), 19. 37 a) + b), 19. 41 a) from friday the balanced redox equation is: Cl- cl2 first balance the elements. Now place 14 h+ atoms in the reactants. Now for the second half of the reaction. 2 + 6cl- 2cr+3 + 7h2o + 3cl2. Cn- + mno4 first balance as if you were in acid. Cn- + h2o cno- + 2h+ + 2e- But: h+ cannot exist in any concentration in basic solution . Mno2 + 2h2o these h+ are removed by adding an appropriate amount of oh- so: in the cn- reaction, 2oh- are added to both sides recall 2oh- + 2h+ 2h2o. 2oh- + h2o + cn- cno- + 2h2o + 2e- 2oh- + cn- cno- + h2o + 2e- the waters cancel out. Mno4- of the reaction 4oh- 3e- + 2h2o + mno4- mno2 + 4oh- fix electrons. 6oh- + 3cn- + 4h2o + 2mno4 simplify further.