CHEM 1050 Lecture Notes - Lecture 12: Joule, Boiling Point, Reaction Rate Constant

74 views3 pages

Document Summary

Review questions products are not favour so not negative value. Multiple choice questions: at 298k, keq = 4. 34 10, 17. 6 kj. 5 for the reaction: ph3(g) + hi(g) ph4i(s). Go= -237. 2 kj/mol temp changes, liquid and gas reached equilibrium: the boiling point of ch3cooh(l) can be calculated to be, 153 c, 0. 426 c. Wstch units: 799 c, 153 c, the oxidation state of p in na2hpo4 is, 1. Na= +1 h=+1 o= -2: +5, +3, given zn(s) + sn2+ (aq) sn(s) + zn2+ (aq) 9: 2. 5 104 (aq) + br (aq) + hobr(aq) at 298k is, 4. 1 10. 4: a current is passed through a molten mixture of zni2 and kcl. The product at the cathode is: cl, i2, zn, k, use the following experimental data for no(g) + cl2(g) nocl2(g) molten= no water. The order of cl2(g) in the rate law is: 1, none of these x2.

Get access

Grade+20% off
$8 USD/m$10 USD/m
Billed $96 USD annually
Grade+
Homework Help
Study Guides
Textbook Solutions
Class Notes
Textbook Notes
Booster Class
40 Verified Answers
Class+
$8 USD/m
Billed $96 USD annually
Class+
Homework Help
Study Guides
Textbook Solutions
Class Notes
Textbook Notes
Booster Class
30 Verified Answers

Related textbook solutions

Related Documents

Related Questions