BIOL 1090 Lecture Notes - Lecture 7: Allosome, Atlantic University Sport, Chromosome
26 Oct 2015
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Consider a couple, each heterozygous for a recessive allele that causes a serious disease in homozygous individuals. First, let"s look at all of the 5 possibilities (u=unaffected, a=affected): 4 is the number of children; 3 is the number of unaffected and 1 is the number of affected. Now we will use math to figure out this part. Let"s call the unaffected kids x" and probability of them being unaffected p". Let"s call the affected child y" and his/her probability q". The solution to the previous problem is: ehffffehefdjdsdhsjhdshdjsjsdjd ( )3( )1 = 4 x (27/64) x (1/4) = 108/256 or 0. 42. Is albinism recessive or dominant: from the pedigree, albinism appears to be a recessive trait, s is therefore homozygous recessive for a, r has siblings with albinism, so there is some risk that r is a carrier (heterozygous. Aa: the risk of t having albinism therefore depends on two factors: the probability that.
