ENCI 595 Lecture Notes - Lecture 3: Cylinder Stress, Ultimate Tensile Strength, Structural Load
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We know: w = 20 kn/m (including self weight) max defl: L = 4. 2 m (200 mm for each bearing) E = 850f"m = 9350 mpa (clause 6. 5. 2) I cr (weighted average i over cracked and uncracked zones) f t f cs y t. = mpa (table 5) fcs = compressive axial stress. Io = 290(590)3/12 = 4. 96 x 109 mm4 yt = Ma = maximum moment due to specified load. Consider equilibrium of the moments of area about the n. a. b(kd)(kd/2) = nas(d-kd) divide both sides by bd2/2: (quadratic equation, use quadratic formula) k = (as = bd) Back to example 2: n = 200000/9350 = 21. 39, = 0. 0028 k k = 0. 292. 1 50 " where s is time dependent. S = 1 for loads sustained 5 yrs and up. S = 0. 7 for loads sustained 1 yr. S = 0. 6 6 mths. S = 0. 5 3 mths.