STAT151 Lecture : Analysis of Variance
STAT151 Full Course Notes
Document Summary
Get access
Related textbook solutions
Related Documents
Related Questions
APLIA STATISTICS
The results of the study are presented in the following data table. All scores are times necessary to complete the paper folding-task, recorded in seconds.
Noise Type
Participant | Classical Music | White Noise | Nature Sounds | Participant Totals | |
A | 3.22 | 3.42 | 3.46 | P=10.10 | n= 5 |
B | 3.27 | 3.31 | 3.35 | P=9.93 | k=3 |
C | 3.47 | 3.93 | 3.69 | P=11.09 | N=15 |
D | 3.43 | 3.91 | 3.74 | P=11.08 | G=53.33 |
E | 3.35 | 4.16 | 3.82 | P=11.33 | |
T = 16.74 | T = 18.73 | T = 18.06 | |||
SS = 0.0441 | SS = 0.5286 | S = 0.1575 |
The three treatments in the experiment define three populations of interest. You use an ANOVA to test the hypothesis that the three population means are equal. Present the results of your analysis in the following ANOVA table by entering the missing df values df and selecting the correct values for the missing SS, MS and F entries. (Note: For best results, retain at least two additional points throughout your calculations. Depending on the order in which you do these calculations and the number of digits you retain, you may find slight rounding differences in the last digit between your answers and the answer choices"
ANOVA
Source | SS | df | MS | F |
Between treatments | ||||
Within treatments | 0.0609 | |||
Between subjects | 0.1372 | |||
Error | ||||
Total | 14 |