CHEM103 Lecture 5: Ions, Periodic Table, Trends in Atomic Properties

ww sapli glearning.com/b scrms mod bis/view.php?id=47 - -C s. Un e sity of Southern Missi x Search Tuto Learning gUniversity of Southern Mississippi- CHE 107 - Spring18-BROOME Activities and Due Dates 13 ts Score 3/7/2018 11:59 PM 424/100 Print il Calculator Ed Periodic Table Question 10 of 26 Sapling Learning Rearrange this expression into quadratic form, axtbx+c o 0.20- 75-x where a “ 1, and identify the values of D and Number 100 Would you like to store your password for saplingleaming.com? More info a e

k = 1.381 times 10^29 J/K h = 6.626 times 10^-24 J-s h = h/2 pi R = 8.315 J/K-mol (constant de los gases) 8.315 times 10^2 L-bar/K-mol 1.987 cal/K-mol 8.206 times 10^2 L-atm/K-mol c = 2.99 times 10^10 cm/s R = 109.677.59 cm^4 (constant de Rydberg) N_ = 6.02 times 10^23 (numero de Avogadro) Conversiones 101.325 N/m2 = 1 atm 4.184 J = 1 cal 1.01325 bar = 1 atm 10^-3 m^3 = 1 L 133.32 Pa = 1 torr 1 J = 1 N-m 1N = 1 kg-m/s^2 Formulas E_v = hv_s(v + 1/2) E_ = h^2/2i J(J + 1) = J(J + 1)B, h B_ = h/8 pi^2 mu r^2 I = mu r^2_ Delta E = hv c = lambda v mu = m_1 m_2/m_1 + m_2 P_ = -ih partial differential/partial differential x v = 1/2 pi Squareroot k/mu alpha = Squareroot k mu/h = 2 pi v mu/h E_ = E_ + hv_ (v + 1/2) - hv_ x_ (v + 1/2)^2 + hB_ J (J + 1) - h alpha_ (v + 1/2) J(J + 1) integral sin^2 cxdx = x/2 - (1/4c) sin 2cx H_ = -h^2/2m d^2/dx^2 H_ = - h^2/2m d^2/dx^2 + 1/2 kx^2 H_ = - h^2/2 mu r^2_ [1/sin theta partial differential/partial differential theta(sin theta partial differential/partial differential phi^2] E_ = n^2 h^2/8ma^2 E_ = h^2/8m (n^2_/a^2 + n^2_/b^2 + n^2_/c^2) Delta E = hv c = lambda v B = h/8 pi^2 I_ I_ = mu r^2_ v = 1/2 pi Squareroot k/mu Phi_ = Squareroot 2/a sin n pi x/a integral^_ e^dx = 1/2 (pi/b)^1/2 integral^_ x^2x + 1 e^dx = pi !/2a^integral^_ x^e^dx = (1)(3)(5) (2 pi - 1)/2^a^(pi/a)^1/2