MBB 222 Lecture Notes - Lecture 14: Enzyme Catalysis, Reaction Rate, Enzyme Kinetics

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The complementarity between the enzyme and the transition state helps to convert the substrate to the transition state and thus lowers the activation energy. (cid:396)ep(cid:396)ese(cid:374)ts the high e(cid:374)e(cid:396)g(cid:455) t(cid:396)a(cid:374)sitio(cid:374) state of the su(cid:271)st(cid:396)ate, represents the transition state in the presence of enzyme. For the enzyme (e) catalyzed reaction: s > p. Es and ep (cid:396)ep(cid:396)ese(cid:374)t so(cid:373)e(cid:449)hat sta(cid:271)le i(cid:374)te(cid:396)(cid:373)ediates i(cid:374) the (cid:396)ea(cid:272)tio(cid:374) path(cid:449)a(cid:455). Enzymes function to increase the rate of s > p. More accurately, they allow the system to reach equilibrium more quickly: s = p. The equilibrium between s and p reflects the difference in free energy of their ground states, I(cid:374) the e(cid:454)a(cid:373)ple sho(cid:449)(cid:374), the e(cid:395)uili(cid:271)(cid:396)iu(cid:373) fa(cid:448)o(cid:396)s p (i. e. , at e(cid:395)uili(cid:271)(cid:396)iu(cid:373) there is more p than s). Enzyme kinetics -the study of the rates of chemical reactions the rate (velocity, v) of a reaction is measured as the change in reactant/substrate concentration [s] or product concentration [p] over time.

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