MATH 2007 Lecture 13: 11.3) The Integral Test and Estimates of Sums
17 Dec 2018
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Sue t continuous and decreasing for x 21 and let n l the sequence 5h37 is incresds because a cact tune z actazt can sn y f6 izz nin izz n. in y ha. We get inequalities erztaz. tn an e f tan id f altar 1 follows that. Sn cait tan e crit fffco do tan e c an 2 an ftfcx dx then by f7fcxd. If fz5nzl z kandi o n3edivezes if faddy ea e f is. Thus an converges bounded above so fffcado a andiws fffc. G dx co dice then by it converges f be positive continuous and decreasing fr x 21 and. Theintersultest let an gcn then canconverged ifcfff. co dyce generally. More for x2k then an converges if the conditions ou f are satisfied ifl sf fado l but 67. Lt f is g continuous and decreasy far x 21 c. T let lcd yx so tank get from jake.
