BIOL 3P96 Lecture Notes - Lecture 9: Null Hypothesis, Aspirin, Mosaic Plot
24 Jul 2015
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Biol 3p96 lecture 9: contingency analysis: associations between categorical variables. Tests the independence of two or more categorical variables. Determine to what extent one variable is contingent on the other. H0: the nationality of the bottle of wine purchased and the nationality of the music being played are independent. Ha: the nationality of the bottle of wine purchased and the nationality of the music being played are not independent. Pr[ french wine and french music] = pr[french wine] pr[french music] If h0 is true, pr[french wine and french music] = 0. 634 x 0. 585 = 0. 3711. Count number of rows (r) and number of columns (c) in the data table and use the following formula: Df= (r 1) (c 1) We can reject the null hypothesis of independence, and say that the nationality of the wine sold did depend on what music was played. Expected count for a given cell = (row total x column total) / grand total.
