PHY 101 Chapter Notes -The Sketch, Net Force
2 Dec 2014
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We will break the motion into two stages: (1) an acceleration period and (2) a deceleration period. The angular displacement during the acceleration period is and while decelerating, 7. 12 (a) the angular speed is (b) since the disk has a diameter of 45. 0 cm, its radius is r = (00. 450 m)/2 = 0. 225 m. Thus, when ac = at = 0. 500 m/s2, we have (b) at this time, and the linear displacement is (c) the time is as found in part (b) above. 7. 37 (a) at the midpoint between the two masses, the forces exerted by the 200-kg and 500-kg masses are oppositely directed, so from and. Note that the above equation yields a second solution d = 1. 09 m. at that point, the two gravitational forces do have equal magnitudes, but are in the same direction and cannot add to zero. The sketch at the right shows the car as it passes the highest point on the bump.
