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A 100-gram sample of H2O at 22°C absorbs 8360 joules of heat. What will be the final temperature of the water?
Q= P E = mgh
(5000m3 * 1000/1m^3 kg)*(9.8 m/s^2)(50) <---water
S = Q/T = (2.45*10^9 J)/293K = 8360 KT/K
Q=mCÎT
Find the change in temperature in water
