MATH 1550 Chapter : Webassign 2.3 Answers
4/14/2014 Section 2.3
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Current Score : 100 / 100 Due : Monday, January 27 2014 11:59 PM C ST
1. 5/5 points | Previous Answers SCalcET7 2.3.001.
Given that
find the limits, if they exist. (If an answer does not exist, enter DNE.)
(a)
-6
(b)
-125
(c)
3
(d)
-9
(e)
DNE
(f)
0
Section 2.3 (Homework)
Laura Vavrek
Math 1550 Van Farowe, section 20, Spring 2014
Instructor: Derek Van Farowe
WebAssign
The due date for this assignment is past. Your work can be viewed below, but no changes can be made.
Important! Before you view the answer key, decide whether or not you plan to request an extension. Your Instructor may not grant you an extension if you
have viewed the answer key. Automatic extensions are not granted if you have viewed the answer key.
Request Extension View Key
f(x) = 9 g(x) = −5 h(x) = 0,lim
x→2 lim
x→2 lim
x→2
[f(x) + 3g(x)]
lim
x→2
[g(x)]3
lim
x→2
lim
x→2 f(x)
lim
x→2
5f(x)
g(x)
lim
x→2
g(x)
h(x)
lim
x→2
g(x)h(x)
f(x)
4/14/2014 Section 2.3
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2. 5/5 points | Previous Answers SCalcET7 2.3.002.
The graphs of f and g are given. Use them to evaluate each limit, if it exists. (If an answer does not exist, enter DNE.)
(a)
2
(b)
DNE
(c)
0
(d)
DNE
(e)
16
(f)
2
[f(x) + g(x)]
lim
x→2
[f(x) + g(x)]
lim
x→1
[f(x)g(x)]
lim
x→0
lim
x→−1
f(x)
g(x)
[x3f(x)]
lim
x→2
lim
x→1 3 + f(x)
4/14/2014 Section 2.3
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3. 5/5 points | Previous Answers SCalcET7 2.3.010.
(a) What is wrong with the following equation?
(b) In view of part (a), explain why the equation
is correct.
4. 5/5 points | Previous Answers SCalcET7 2.3.011.
Evaluate the limit, if it exists. (If an answer does not exist, enter DNE.)
2
= x + 3
x2 + x − 6
x − 2
The left-hand side is not defined for x = 0, but the right-hand side is.
The left-hand side is not defined for x = 2, but the right-hand side is.
None of these — the equation is correct.
(x − 2)(x + 3) ≠ x2 + x − 6
= (x + 3) lim
x → 2
x2 + x − 6
x − 2lim
x → 2
Since the equation holds for all x ≠ 2, it follows that both sides of the equation approach the same limit as x →
2.
This equation follows from the fact that the equation in part (a) is c orrect.
None of these — the equation is not correct.
Since and x + 3 are both c ontinuous, the equation follows.
x2 + x − 6
x − 2
lim
x → 4
x2 − 6x + 8
x − 4
Document Summary
Due : monday, january 27 2014 11:59 pm cst. The due date for this assignment is past. Your work can be viewed below, but no changes can be made. Math 1550 van farowe, section 20, spring 2014. Before you view the answer key, decide whether or not you plan to request an extension. Your instructor may not grant you an extension if you have viewed the answer key. Automatic extensions are not granted if you have viewed the answer key. f(x) = 9 g(x) = 5 lim x 2 find the limits, if they exist. (if an answer does not exist, enter dne. ) h(x) = 0, Request extension view key: 5/5 points | previous answers. 0 lim lim lim x 2 x 2 x 2 x 2 x 2 x 2 lim lim lim http://www. webassign. net/web/student/assignment-responses/last?dep=8379543. The graphs of f and g are given.
