EE 2950 Chapter : Chapter 04
Document Summary
The voltage across the circuit is given by equation 4. 8: Rct in which vi is the initial voltage. At the time t1% for which the voltage reaches 1% of the initial value, we have. Taking the natural logarithm of both sides of the equation, we obtain. Solving and substituting values, we find t1% = 4. 605rc = 23. 03 ms. The exponential transient shown in figure 4. 4 is given by. Taking the derivative with respect to time, we have tdv. Thus the steady-state (i. e. , t approaching infinity) equivalent circuit is: From this circuit, we see that as: 50 . A v a ri: 2 ai. E4. 4 (b) the dc steady-state equivalent circuit is: Here the two 10- resistances are in parallel with an equivalent resistance of 1/(1/10 + 1/10) = 5 . This equivalent resistance is in series with the 5- resistance.
