PHYS 1070 Chapter 3: Study Guide 3

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tanmallard797

28 Feb 2017

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Oine incident ray , reflected ray and normal all lie in a common plane the ratio of speed ( c ) of light in a vacuum to the speed ( v ) in a medium termed the refractive. Index ( n ) of the medium , so n. C then refractive indices of all transparent material media are numbers greater than. Sneltslawn ,smo , nzsinoz fxampietst a) b) c) A light ray passes from air to water making an angle ( in air wl the normal of. What is the speed ray of makes with the normal in water ( oz ) light in water. What is the angle of from glass refraction ? to water making an angle in the glass of. 620mm inavacuum what are the wavelength , frequency , and speed of this light in the ( n. What is the speed of light in the second medium.

Related Questions

In Example 33.11, the water-glass interface is horizontal. If instead this interface were tilted 15.0° above the horizontal, with the right side higher than the left side, what would be the angle from the vertical of the ray in the glass? (The ray in the water still makes an angle of 60.0° with the vertical).

EXAMPLE 33.11: Reflection and refraction

In Fig 33.11, material a is water and material b is a glass with an index of refraction 1.52. If the incident ray makes an angle of 60.0° with the normal, find the directions of the reflected and refracted rays.

SOLUTION

IDENTIFY: This is a problem in geometric optics. We are given the incident angle and the index of refraction of each material, and we need to find the reflected and refracted angles.

SET-UP: Figure 33.11 shows the rays and angles for this situation. The target variables are the reflected angle θ_r and the refracted angle θ_b. Since n_b is greater than n_a, the refracted angle must be smaller than the incident angle θ_a; this is shown in the figure.

EXECUTE: According to Eq 33.2, the angle the reflected ray makes with the normal is the same as that of the incident ray so θ_r= θ_a=60.0°.

To find the direction of the refracted ray, we use Snell’s law, Eq 33.4, with n_a=1.33, n_b=1.42, and θ_a=60.0°. We find:

EVALUATE: The second material has a larger refractive index than the first, just like the situation shown in Fig 33.8a. Hence, the refracted ray is bent toward the normal as the wave slows down upon entering the second material and θ_b< θ_a.

Figure 33.11. Reflection and refraction of light passing from water to glass

Figure 33.8. Reflection and refraction in three cases. (a) Material b has a larger index of refraction than material a. (b) (a) Material b has a smaller index of refraction than material a. (c) The incident light ray is normal to the interface between the materials.

burgundysnake577

Every transparent material can be characterized by what is called its index of refraction, n, given by the equation

$Chapter 9, Problem 4C, Every transparent material can be characterized by what is called its index of refraction, n, given , example 1$

Here c is the speed of light in a vacuum and v is the speed of light in the transparent material. Although normal air is not quite a vacuum, its density is small enough that v_a_i_ris approximately equal to c, so that we may take $Chapter 9, Problem 4C, Every transparent material can be characterized by what is called its index of refraction, n, given , example 2$ without too much error.
The precise mathematical relationship between the angles of incidence and refraction is given by what is known as Snell’s law,

$Chapter 9, Problem 4C, Every transparent material can be characterized by what is called its index of refraction, n, given , example 3$
where n₁and A₁are the index of refraction and the angle between the light ray and the normal, respectively, in medium 1, and n₂and A₂are the corresponding quantities for medium 2.

(a) Using the information in Table 9.1, compute the index of refraction for water and for fused silica (glass).
(b) Verify the result in Example 9.2 using Snell’s law explicitly. Show, using the same relationship, that the values for the angles of refraction in air (medium 2) in panels (b), (c), (d), and (e) of Figure 9.36 are correct for the given angles of incidence in glass (medium 1).

whitebuffalo354

You will be utiizing a basicoptic system.

The index of refraction of theplastic cylindrical lens depends on wavelength. Choose an anglewhich gives a good color separation and measure the index ofrefraction for blue and red light.

Question:How big is the difference in indices of refraction? How good is theapproximation that n is constant for thismaterial?

If this question doesnt make sense..then just answer ittheoretically speaking. That is how would we go about checkingwhether or not it conforms with the n as the constant for thematerial... Thanks!

Background info:

ThePhysics

The Law ofReflection

The law of reflection states that for a plane mirror, the angle ofincidence is equal to the angle of reflection, and that the tworays lie in a plane.

normal

. A light ray perpendicular to the surface has an angle ofincidence 0Â°.

The Law of Refraction âSnellâs Law

A ray of light passing from one substance (index ofrefraction

n_{1)into another (index of refraction n}

2) across a plane boundary will be refracted. The angle the raymakes in one medium will be related to the angle in the secondmedium by the equation below, and that all rays lie in aplane.

(2)

Total InternalReflection

A ray incident on a medium with lower index of refraction willbe

totally internally reflected if sin Î¸1> n2/n1.There will be no transmitted beam for this incident angle. Ameasurement of the critical angle for total internalreflection can be used to determine the index of refraction of the substance.If n

2 = 1 (air), then the critical angle is:

sin Î¸c = 1/

1. (3)

Polarization byReflection â Brewsterâs Angle

If the angle between the reflected and refracted rays is 90Â°,then

tan Î¸

B = n2/n

1. (4)

At this angle, only light with polarization out of the plane ofreflection and refraction will be reflected. The reflected lightwill be completely polarized.

Figure3.

Refractionof Light Rays

Figure2.

Incidentand Reflected Rays

(1)

Always measure the angles with respect to the surface

PHYS 1070 Chapter 3: Study Guide 3

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