MATH 122 Midterm: MATH 122 Harvard Midterm 2 Solutions122 Fall 05

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15 Feb 2019
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Question 1 (true or false) - 2 points each. Question 2 - 15 points: sylow theorems: Given a group g of order pnm: there exists a sylow p-subgroup, all sylow p-subgroups are conjugates, the number of sylow p-subgroups divides m and congruent to 1 (mod p), consider a group of 35 = 5. 7 elements. By the sylow theorems, there is exactly one sylow 5-subgroup and another sylow 7-subgroup, both are normal subgroups of g. an element of g can only have order 1, 5, 7 or 35 (divisors of 35): There are 4 elements of order 5, thus there must be 35-(1+4+6)=24 ele- ments of order 35. Each of these elements generate a 35 element cyclic sub group, which is the whole group we are considering. Question 3 - 8 points: de ne t = {s s|gs = g, the order of the set s is the sum of the disjoint orbits, thus by stabilizer-

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