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31 Dec 2021
Problem 35
Page 912
Section: Problems
Chapter 31: Nuclear Energy; Effects and Uses of Radiation
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31 Dec 2021
Given information
We need to find the quantity of natural water needed to run a 1150 MW reactor assuming 33% efficiency.
Step-by-step explanation
Step 1.
Assume that the two reactions take place at equal rates, so they are both equally likely. Then from the reaction of 4 deuterons, there would be a total of 7.30 MeV of energy released, or an average of 1.825 MeV per deuteron. A total power of 1150 MW /0.33= 3485 MW must be obtained from the fusion reactions to provide the required 1150-MW output, because of the 33% efficiency
Reaction is 
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Physics: Principles with Applications
7th Edition, 2013
Giancoli
ISBN: 9780321625922
Solutions
Chapter
Section
- Problem 1
- Problem 2
- Problem 3
- Problem 4a
- Problem 4b
- Problem 5
- Problem 6a
- Problem 7a
- Problem 7b
- Problem 8a
- Problem 8b
- Problem 9
- Problem 10
- Problem 11
- Problem 12a
- Problem 12b
- Problem 13a
- Problem 13a
- Problem 13b
- Problem 13c
- Problem 14
- Problem 15
- Problem 16
- Problem 17
- Problem 18
- Problem 19
- Problem 20
- Problem 21a
- Problem 21b
- Problem 22
- Problem 23
- Problem 24
- Problem 25
- Problem 26
- Problem 27
- Problem 28
- Problem 29
- Problem 30
- Problem 31a
- Problem 31b
- Problem 32
- Problem 33
- Problem 34a
- Problem 34b
- Problem 35
- Problem 36
- Problem 37
- Problem 38a
- Problem 38b
- Problem 39
- Problem 40
- Problem 41
- Problem 42
- Problem 43a
- Problem 43b
- Problem 44
- Problem 45
- Problem 45
- Problem 46
- Problem 47
- Problem 48
- Problem 49
- Problem 50a
- Problem 50b
- Problem 50c
- Problem 51a
- Problem 51b
- Problem 52a
- Problem 52b
- Problem 52c
- Problem 52d
- Problem 53