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Problem 31c
Page 423
Section: Problems by Topic
Chapter 10: Chemical Bonding II: Molecular Shapes, Valence Bond Theory,and Molecular Orbital Theory
Textbook ExpertVerified Tutor
13 Nov 2021
Given information
The given molecule is 
.
Step-by-step explanation
Step 1.
has a total of 
valence electrons.
Let us draw the lewis structure by distributing these 
electrons in this structure, with oxygen at the center and fluorine atoms at the terminals.
Oxygen atom forms two single bonds with two fluorine atoms and oxygen has two lone pairs of electrons.
The oxygen atom has four electron domains, two bonding electron domains,s and two nonbonding electron domains. Hence it has a tetrahedral structure.
And the hybridization of oxygen in this molecule is 
.
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Principles of Chemistry Molecular Approach
3rd Edition, 2014
Tro
ISBN: 9780321971944
Solutions
Chapter
Section
- Problem 1
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- Problem 3a
- Problem 3b
- Problem 3c
- Problem 4a
- Problem 4b
- Problem 4c
- Problem 5a
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- Problem 5c
- Problem 5d
- Problem 6a
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- Problem 9d
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- Problem 10c
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- Problem 12c
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- Problem 14a
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- Problem 31a
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- Problem 31c
- Problem 31d
- Problem 32a
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- Problem 32c
- Problem 32d
- Problem 33a
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- Problem 33c
- Problem 33d
- Problem 34a
- Problem 34b
- Problem 34c
- Problem 34d
- Problem 35a
- Problem 35b
- Problem 35c
- Problem 36a
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- Problem 36c
- Problem 37
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- Problem 40
- Problem 41
- Problem 42
- Problem 43
- Problem 44
- Problem 45a
- Problem 45b
- Problem 45c
- Problem 45d
- Problem 46a
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- Problem 46c
- Problem 46d
- Problem 47a
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- Problem 47c
- Problem 47d
- Problem 48a
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- Problem 48d
- Problem 49
- Problem 50