3 Nov 2021
Problem 31
Page 170
Section: Problems by topic
Chapter 4: Chemical Quantities and Aqueous Reactions
Textbook ExpertVerified Tutor
3 Nov 2021
Given information
For this problem, we need to prepare 
of a 
solution.
We will use the concept of molarity to solve for the amount (in grams) of 
needed to prepare this solution.
Step-by-step explanation
Step 1.
First, we will calculate the number of moles of required using the molarity equation. Convert 
to 
.
required using the molarity equation. Convert to .
Therefore the amount of needed (in mol) to prepare 
of a solution is 
needed (in mol) to prepare of a solution is Next, we will convert 
to grams using its molar mass of 
to grams using its molar mass of 
Therefore, the amount of needed (in g) to prepare of a 
solution is 
.
needed (in g) to prepare of a solution is .Unlock all Textbook Solutions
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Solutions
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