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3 Feb 2018

5. If det 211 212 213 (3a11 +231 021 + 3a11 a31 +011 | a21 422 023) = -3, then det 3a12 + 232 022 + 3012 a32 + 212 ) has the value 231 232 233 3013 + 233 223 + 3013 033 +213) (A) – 3 (B) 3 (C)0 (D) 18 (E) None of the above..

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Trinidad Tremblay
Trinidad TremblayLv2
3 Feb 2018
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