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3. If det au 012 013 221 222 223 231 232 233) (A) 6 (B) (3a11 +231 3012 + 232 3013 + 233 = 4, then det 221 +211 222 +212 223 +013 has the value 231 + 2011 232 + 2a12 033 + 2013 - 6 (C) – 12 (D) 4 (E) None of the above.

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Nestor Rutherford
Nestor RutherfordLv2
3 Jan 2018
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Related textbook solutions

Introductory Statistics
OER Edition, 2013
Openstax
ISBN: 9781938168208

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