1
answer
0
watching
83
views
ambermole700Lv1
13 Apr 2020
Arithmetic-Geometric Mean Inequality If a1, a2, . . . , an are nonnegative numbers, then their arithmetic mean is
, and their geometric mean is
. The arithmetic-geometric mean inequality states that the geometric mean is always less than or equal to the arithmetic mean. In this problem we prove this in the case of two numbers x and y. Prove the arithmetic-geometric mean inequality
Arithmetic-Geometric Mean Inequality If a1, a2, . . . , an are nonnegative numbers, then their arithmetic mean is, and their geometric mean is. The arithmetic-geometric mean inequality states that the geometric mean is always less than or equal to the arithmetic mean. In this problem we prove this in the case of two numbers x and y. Prove the arithmetic-geometric mean inequality
Patrina SchowalterLv2
24 May 2020
and sides 
and 
.
and 
, use these criteria to find the range of values of 
has two solutions, one solution, or no solution.
=0 is of quadric type. We can solve it by letting 
and 
, and factoring. Or we could solve for 
, square each side, and then solve the resulting quadric equation. Solve the following equations using both methods indicated, and show that you get the same final answers.
quadratic type; solve for the radical, and square.
quadratic type; multiply by LCD