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18 Dec 2019

Calculate the freezing point of a solution of 60.0 g of NaCl(assume complete dissociation) dissolved in 500.0 g of water. Kf =1.86 C/m and Kb = 0.512 C/m

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31 Dec 2019
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Related questions

Assuming complete dissociation of the solute, how many grams of KNO3 must be added to 275 mL of water to produce a solution that freezes at −14.5 ∘C? The freezing point for pure water is 0.0 ∘C and Kf is equal to 1.86 ∘C/m ANSWER=109 g PART B NEEDED: If the 3.90 m solution from Part A boils at 103.45 ∘C, what is the actual value of the van't Hoff factor, i? The boiling point of pure water is 100.00 ∘C and Kb is equal to 0.512 ∘C/m.

Menthol is a crystalline substance with a peppermint taste and odor. When 0.504 g of menthol is dissolved in 25.0 g of cyclohexane, the freezing point of the solution is lowered by 2.69 °C. The freezing point and Kf constant for cyclohexane can be found below. Calculate the molar mass of menthol.

Solvent Formula Kf value*

(°C/m)

Normal freezing

point (°C)

 Kb value

(°C/m)

Normal boiling

point (°C)
water H2O 1.86 0.00 0.512 100.00
benzene C6H6 5.12 5.49 2.53 80.1
cyclohexane C6H12 20.8 6.59 2.92 80.7
ethanol C2H6O 1.99 –117.3 1.22 78.4
carbon
tetrachloride 		CCl4 29.8 –22.9 5.03 76.8
camphor C10H16O 37.8 176

Boiling Point Elevation/Freezing Point Depression T = m K Where: T = T(solution) - T(pure solvent) * m = (# moles solute / Kg solvent) Kb = boiling point elevation constant. Kf = freezing point depression constant. Kb and Kf depend only on the SOLVENT. Below are some common values. Use these values for the calculations that follow.

Solvent Formula Kb(c/m) Kr(c/m)

water H2O 0.512 -1.86

Ethanol CH3CH2OH 1.22 -1.99

Chloroform CHCl3

Benzene C6H6 2.53 -5.12

Diethyl ether CH3CH2OCH2CH3

*Please note that ΔT as defined above will be a negative number for freezing point depression. Therefore, Kf must also be given as a negative number

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