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A sample of 0.1364 g of an unknown monoprotic acid was dissolved in 20.0 mL of water and titrated with 0.080M NaOH. The acid required 23.0 mL of base to reach the equivalence point.
(a) What is the molar mass of the acid in (g/mol)?
(b) After 12.0 mL of base had been added in the titration, the pH was found to be 5.78. What is the Ka for the unknown acid?
A sample of 0.1364 g of an unknown monoprotic acid was dissolved in 20.0 mL of water and titrated with 0.080M NaOH. The acid required 23.0 mL of base to reach the equivalence point.
(a) What is the molar mass of the acid in (g/mol)?
(b) After 12.0 mL of base had been added in the titration, the pH was found to be 5.78. What is the Ka for the unknown acid?
chalk-eduLv10
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