the marketing research department for a company that producesdigital cameras, arrived the the following price-demand revenue andcost function:
p(x) = 94.8 - 5x
R(x) = x(94.8 - 5x)
C(x) = 156 + 19.7x
Where p(x) is the whole sale price per camera at which x millioncameras can be sold. Both revenue and cost functions are in milliondollars with 0 <=x <= 15.
1- Find the value of x to the neareset thousand cameras thatwill produce the maximum revenue. What is the maximum revenue tothe neares thousand dollars.
2- Find the break-even points algebraically to the nearesthousand cameras.
3- For what values of x will a loss occur ?? A profit?
please show me the solution in details, if you can dothe answer on a paper in details and graphs and scan the paperhere, it will be great.
the marketing research department for a company that producesdigital cameras, arrived the the following price-demand revenue andcost function:
p(x) = 94.8 - 5x
R(x) = x(94.8 - 5x)
C(x) = 156 + 19.7x
Where p(x) is the whole sale price per camera at which x millioncameras can be sold. Both revenue and cost functions are in milliondollars with 0 <=x <= 15.
1- Find the value of x to the neareset thousand cameras thatwill produce the maximum revenue. What is the maximum revenue tothe neares thousand dollars.
2- Find the break-even points algebraically to the nearesthousand cameras.
3- For what values of x will a loss occur ?? A profit?
please show me the solution in details, if you can dothe answer on a paper in details and graphs and scan the paperhere, it will be great.
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