1
answer
0
watching
78
views
26 Oct 2021
Hi! I think I solved this, I just wanted to confirm which isright :)
f(x) = e/pi
Quotient rule: f'(x) = [pi*e - e(0)]/pi^2 = (pi*e)/pi^2 =e/pi
Since the derivative of e^x is e^x, I'm assuming the derivativeof e is e then? Or is it a constant and thus 0? If that's the casethen:
f'(x) = [pi(0) - e(0)]/pi^2 = (0-0)/pi^2 = 0/pi^2 = 0
Which solution is correct? Or are neither correct?
Hi! I think I solved this, I just wanted to confirm which isright :)
f(x) = e/pi
Quotient rule: f'(x) = [pi*e - e(0)]/pi^2 = (pi*e)/pi^2 =e/pi
Since the derivative of e^x is e^x, I'm assuming the derivativeof e is e then? Or is it a constant and thus 0? If that's the casethen:
f'(x) = [pi(0) - e(0)]/pi^2 = (0-0)/pi^2 = 0/pi^2 = 0
Which solution is correct? Or are neither correct?
1
answer
0
watching
78
views
For unlimited access to Homework Help, a Homework+ subscription is required.
chardrich888Lv3
1 Nov 2021
Unlock all answers
Get 1 free homework help answer.
Already have an account? Log in