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15 Oct 2022
If
f1[k]*f2[k]=c[k]
then
f1[k-m]*f2[k-n]=c[k-m-n]
If
f1[k]*f2[k]=c[k]
then
f1[k-m]*f2[k-n]=c[k-m-n]
15 Oct 2022
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If
f1[k]*f2[k]=c[k]
then
f1[k-m]*f2[k-n]=c[k-m-n]
