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19 Nov 2019
Solve for x: det[x -1 3 1-x] = det [ 1 0 -3 2 x -6 1 3 x-5] 22. without directly evaluating the determiant, show that det[six x cos x sin (x+s) sin beta cos beta sin (beta+s) sin cos sin( +s)]=100
Solve for x: det[x -1 3 1-x] = det [ 1 0 -3 2 x -6 1 3 x-5] 22. without directly evaluating the determiant, show that det[six x cos x sin (x+s) sin beta cos beta sin (beta+s) sin cos sin( +s)]=100
14 May 2023
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Jean KeelingLv2
2 Jul 2019
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