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18 Nov 2019
Please answer all three please!!!! Find the derivative of the function. p = (q^7 + 4/2q) (q^8 + 6/q) dp/dq = 17/2 q^16 + 20q^9 + 27q^8 - 24/q^3 dp/dq = 13/2 q^12 - 24/q^3 dp/dq = 13/2 q^12 + 12q^5 + 15q^4 - 24/q^3 dp/dq = 1/2 q^12 + 2q^5 + 3q^4 + 24/q^3 y = x^2 + 8x + 3/squareroot x y' = 3x^2 + 8x - 3/x y' = 3x^2 + 8x - 3/2x^3/2 y' = 2x + 8/x y' = 2x + 8/2x^3/2 y = (x - 8) (x^2 + 4x)/x^3 dy/dx = x - 64/x^2 - 64/x^3 dy/dx = 4/x^2 + 64/x^3 dy/dx = 64 + 64/x dy/dx = 12/x^2 - 64/x^3
Please answer all three please!!!!
Find the derivative of the function. p = (q^7 + 4/2q) (q^8 + 6/q) dp/dq = 17/2 q^16 + 20q^9 + 27q^8 - 24/q^3 dp/dq = 13/2 q^12 - 24/q^3 dp/dq = 13/2 q^12 + 12q^5 + 15q^4 - 24/q^3 dp/dq = 1/2 q^12 + 2q^5 + 3q^4 + 24/q^3 y = x^2 + 8x + 3/squareroot x y' = 3x^2 + 8x - 3/x y' = 3x^2 + 8x - 3/2x^3/2 y' = 2x + 8/x y' = 2x + 8/2x^3/2 y = (x - 8) (x^2 + 4x)/x^3 dy/dx = x - 64/x^2 - 64/x^3 dy/dx = 4/x^2 + 64/x^3 dy/dx = 64 + 64/x dy/dx = 12/x^2 - 64/x^3
11 Mar 2023
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Deanna HettingerLv2
22 Jul 2019
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