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In 15 L vessel 1.5 mol Co and 4.5 Mol H2  mixture react at 900 degree celcius. calculate all substance equilibrium concentration.equlibrium constant  is 3.92. reaction Co+3H2=CH4+H2O 

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Related questions

Carbon monoxide and hydrogen react according to the chemical equation shown below. When 1.000 mol CO and 3.000 mol H2 are placed in a 10.00 L vessel at 927 oC and allowed to come to equilibrium, the mixture is found to contain 0.387 mol H2O. What is the molar composition of the equilibrium mixture (how many moles of each substance are present)?CO(g) + 3H2(g) ? CH4(g) + H2O(g) ?

A mixture of 0.01484 mol of H2O, 0.07019 mol of CH4, 0.01819 mol of CO, and 0.09015 mol of H2 is placed in a 1.0-L steel pressure vessel at 1239 K. The following equilibrium is established:

1 H2O(g) + 1 CH4(g)--> 1 CO(g) + 3 H2(g)

At equilibrium 0.01097 mol of H2O is found in the reaction mixture.

(a) Calculate the equilibrium partial pressures of H2O, CH4, CO, and H2.

Peq(H2O) =

Peq(CH4) =

Peq(CO) = .

Peq(H2) = .

(b) Calculate KP for this reaction.

KP =

Carbon monoxide and hydrogen react according to the chemicalequation shown below. When 1.000 mol CO and 3.000 mol H2 are placedin a 10.00 L vessel at 927 oC and allowed to come to equilibrium,the mixture is found to contain 0.387 mol H2O. What is the molarcomposition of the equilibrium mixture (how many moles of eachsubstance are present)? CO(g) + 3H2(g) <-->CH4(g) + H2O(g)

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