The equilibrium partitioning of a chemical in a three-phase system comprised of air, soil and water can be approximated as follows:
Total mass = mass in air + mass in water + mass in soil
= (Vair)(Cair) + (Vwater)(Cwater) + (Vsoil)(Csoil)
Assume a system with a volume 1 L that it is divided into 600 mL water, 200 mL air and 200 mL soil. The soil has a bulk density (rb) of 2.0 g/cm3 and a fraction organic matter of 2.5 percent. Into this system we introduce 100 mg pyrene, which has a Henryâs Law constant of 102.05 (mol/L-atm) and log Kow = 5.13 (L/kg). What would the mass of pyrene be in the air, soil and water phases at equilibrium? How does this compare to our estimate conducted in class? (Hints: pay attention to the units and determine a dimensionless Henryâs Law constant, which the text discusses)
The equilibrium partitioning of a chemical in a three-phase system comprised of air, soil and water can be approximated as follows:
Total mass = mass in air + mass in water + mass in soil
= (Vair)(Cair) + (Vwater)(Cwater) + (Vsoil)(Csoil)
Assume a system with a volume 1 L that it is divided into 600 mL water, 200 mL air and 200 mL soil. The soil has a bulk density (rb) of 2.0 g/cm3 and a fraction organic matter of 2.5 percent. Into this system we introduce 100 mg pyrene, which has a Henryâs Law constant of 102.05 (mol/L-atm) and log Kow = 5.13 (L/kg). What would the mass of pyrene be in the air, soil and water phases at equilibrium? How does this compare to our estimate conducted in class? (Hints: pay attention to the units and determine a dimensionless Henryâs Law constant, which the text discusses)
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