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The active ingredient in many hair bleaches is hydrogen peroxide, H2O2. The amount of hydrogen peroxide present can be determined by titration with a standard permanganate, MnO4, solution: 2 MnO4?(aq) + 5 H2O2(aq) + 6 H+(aq) ---> 5 O2 (g) + 2 Mn+2 (aq) + 8 H2O (l)Calculate the molarity of hydrogen peroxide if 28.75 mL of hydrogen peroxide produced 695 mL of oxygen gas at 0.950 atm and 315 K?

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Related questions

Hydrogen peroxide, H2O2, can be determined by titration with permanganate solution. If it required 80.0 mL of 0.0220 molar MnO4-(aq) solution to titrate 5.0 mL of a H2O2(aq) solution, what is the molarity of the H2O2(aq) solution? The reaction is: 2 MnO4-(aq) + 5 H2O2(aq) + 6 H+ → 5O2(g) + 2 Mn2+(aq) + 8 H2O.

Be sure to answer all parts. The active agent in many hair bleaches is hydrogen peroxide. The amount of H2O2 in 14.5−g of hair bleach was determined by titration with a standard potassium permanganate solution: 2 MnO4−(aq) + 5 H2O2(aq) + 6 H+(aq) → 5 O2(g) + 2 Mn2+(aq) + 8 H2O(l) (a) For the titration, how many moles of MnO4− were required if 40.8 mL of 0.154 M KMnO4 was needed to reach the end point? Write your answer to the correct number of significant figures. Enter your answer in scientific notation. ______ × 10 mol MnO4− (b) How many moles of H2O2 were present in the 14.5 g sample of bleach? Write your answer to the correct number of significant figures. ____ mol H2O2

Using a 25.00 mL of 3.00% by mass solution ({mass H2O2/masssolution}*100) of hydrogen peroxide. Assume the density of thissolution is 1.000 g/mL. If all of the hydrogen peroxide decomposesto water and oxygen according to the reaction

2 H2O2 (aq) <----> 2 H2O (l) + O2 (g)

What is the total volume of oxygen gas generated if the temperatureis 24 degrees Celsius and the pressure is 770 Torr (760 Torr=1atm)? (R=0.08206 L*atm/K*mol) (At this point you can ignore theeffect of water vapor)

Any assistance would be great, its been awhile since I have had anychemistry and don't know how to approach this. I have an idea ofhow to do it, but I haven't done some of the simple stuff in a longtime like converting moles of H2O2 to moles of O2

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