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13 Dec 2019

Find the temperature at which the rate of the reaction would be twice as fast.Ethyl chloride vapor decomposes by the first-order reaction
C2H5Cl→C2H4+HCl
The activation energy is 249 kJ/mol and the frequency factor is 1.6×1014s−1.

Part A Find the value of the specific rate constant at 700 K .

Part B

Find the fraction of the ethyl chloride that decomposes in 20 minutes at this temperature.[C2H5Cl]0−[C2H5Cl]t[C2H5Cl]0[C2H5Cl]0−[C2H5Cl]t[C2H5Cl]0

Part C= Find the temperature at which the rate of the reaction would be twice as fast.

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Patrina Schowalter
Patrina SchowalterLv2
17 Dec 2019

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