Question

XY(aq)?X(aq)+Y(aq)

Qc=[X][Y]/[XY]

Consider mixture B, which will cause the net reaction to proceed forward.

Concentration (M)initial:change:equilibrium:

[XY (I)]0.500(C)?x(E)0.500?x

net??

[X](I)0.100(C)+x(E)0.100+x

+[Y](I)0.100(C)+x(E)0.100+x

The change in concentration, x , is negative for the reactants because they are consumed and positive for the products because they are produced.

Part B

Based on a Kc value of 0.200 and the given data table, what are the equilibrium concentrations of XY , X , and Y , respectively?

Express the molar concentrations numerically.

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Calculating equilibrium concentrations when the net reaction proceeds in reverse

Consider mixture C, which will cause the net reaction to proceed in reverse.

Concentration (M)initial:change:equilibrium:[XY](I)0.200(C)+x(E)0.200+x

?net?

[X](I)0.300(C)?x(E)0.300?x+

[Y](I)0.300(C)?x(E)0.300?x

The change in concentration, x , is positive for the reactants because they are produced and negative for the products because they are consumed.

Part C

Based on a Kc value of 0.200 and the data table given, what are the equilibrium concentrations of XY , X , and Y , respectively?

Express the molar concentrations numerically.