Question

The ativation energy of a certain reaction is 49.6 kj/mol. At 20C , the rate constant is 0.130 s -1. At what temp would thisreaction go twice as fast?

B. Given that the intial rate constant is 0.0130 s -1 at 20 C,what would be the constant at 100 C. Express in inverseseconds

I have been struggling for a while trying to figure this out, Iwould greatly appreciate if someone could show me the steps insloving.

Thanks,

Rachel