A 1.170-g sample of a solid, weak, monoprotic acid is used to make 100.0 mL of solution. 55.0 mL of this solution was titrated with 0.07445-M NaOH. The pH after the addition of 17.77 mL of base was 3.24, and the equivalence point was reached with the addition of 40.84 mL of base.

a) How many millimoles of acid are in the original solid sample? Hint: Don't forget the dilution. mmol acid

b) What is the molar mass of the acid? g/mol

c) What is the pKa of the acid?

pKa =

Question

A 1.170-g sample of a solid, weak, monoprotic acid is used to make 100.0 mL of solution. 55.0 mL of this solution was titrated with 0.07445-M NaOH. The pH after the addition of 17.77 mL of base was 3.24, and the equivalence point was reached with the addition of 40.84 mL of base.

a) How many millimoles of acid are in the original solid sample? Hint: Don't forget the dilution. mmol acid

b) What is the molar mass of the acid? g/mol

c) What is the pKa of the acid?

pKa =

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