A.Assuming you weighed out a 2.3684 g sample of your unknown, and dissolved and diluted it as in the procedure below, and it took 35.63 mL of a 0.1025 M HCl titrant to reach the endpoint, what are the weight percents of Na2CO3 and NaHCO3 in your unknown sample? Solve the simultaneous equations similar to what we did in Ch 27.
Hints:
-Set g Na2CO3 = X
-Eqn A: bicarbonate + carbonate = diluted weighted mass (remember, the mass is not 2.3684, you diluted it before you titrated it. Calculate the diluted g of unknown)
-Convert the g of Na2CO3 to mol of HCl
-Convert the g of NaHCO3 to mol of HCl
-mol HCl = mol HCl from Na2CO3 + mol HCl from NaHCO3
-Before taking the final weight percent, undo the dilution to get back to the original wt % in the unknown
-Na2CO3 + 2HCl â 2 NaCl + H2O + CO2
-NaHCO3 + HCl â NaCl + H2O + CO2
A.Assuming you weighed out a 2.3684 g sample of your unknown, and dissolved and diluted it as in the procedure below, and it took 35.63 mL of a 0.1025 M HCl titrant to reach the endpoint, what are the weight percents of Na2CO3 and NaHCO3 in your unknown sample? Solve the simultaneous equations similar to what we did in Ch 27.
Hints:
-Set g Na2CO3 = X
-Eqn A: bicarbonate + carbonate = diluted weighted mass (remember, the mass is not 2.3684, you diluted it before you titrated it. Calculate the diluted g of unknown)
-Convert the g of Na2CO3 to mol of HCl
-Convert the g of NaHCO3 to mol of HCl
-mol HCl = mol HCl from Na2CO3 + mol HCl from NaHCO3
-Before taking the final weight percent, undo the dilution to get back to the original wt % in the unknown
-Na2CO3 + 2HCl â 2 NaCl + H2O + CO2
-NaHCO3 + HCl â NaCl + H2O + CO2
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