a) How many moles of Al2(SO4)3 are required to make 45 mL of a 0.080 M Al2(SO4)3 solution?
(Hint, molarity is moles per liter. You know the molarity. You are given the number of mL's, which can be converted to liters. Just set it up so the units cancel and you get "moles".)
_____________ moles Al2(SO4)3
b) What is the molar mass of Al2(SO4)3, to the nearest gram?
_____________ [grams/mole]
c) What mass of Al2(SO4)3 is required to make 45 mL of a 0.080 M Al2(SO4)3 solution?
(If you've got moles and molecular weight you can get to grams.)
______________ g Al2(SO4)3
d) How many moles of aluminum ions are present in the solution?
(This is easy. You know how many moles of Al2(SO4)3 there are from part a. Just think about how many aluminum ions there are per Al2(SO4)3.)
______________ mol
a) How many moles of Al2(SO4)3 are required to make 45 mL of a 0.080 M Al2(SO4)3 solution?
(Hint, molarity is moles per liter. You know the molarity. You are given the number of mL's, which can be converted to liters. Just set it up so the units cancel and you get "moles".)
_____________ moles Al2(SO4)3
b) What is the molar mass of Al2(SO4)3, to the nearest gram?
_____________ [grams/mole]
c) What mass of Al2(SO4)3 is required to make 45 mL of a 0.080 M Al2(SO4)3 solution?
(If you've got moles and molecular weight you can get to grams.)
______________ g Al2(SO4)3
d) How many moles of aluminum ions are present in the solution?
(This is easy. You know how many moles of Al2(SO4)3 there are from part a. Just think about how many aluminum ions there are per Al2(SO4)3.)
______________ mol
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