answer

watching

views

11 Dec 2019

Find the solubility of CuI in .29M HCN solution. The ksp of CuI is 1.1 x 10^-12 and the kf for Cu(Cn)2 complex ion is 1 x 10^24. Please help.

answer

watching

406

views

For unlimited access to Homework Help, a Homework+ subscription is required.

Liked by specam9

You have 0 free answers left.
Get unlimited access to 3.8 million step-by-step answers.

Get unlimited access

Already have an account? Log in

Keith LeannonLv2

13 Dec 2019

Unlock all answers

Get 1 free homework help answer.

Already have an account? Log in

Join us on Discord

Chemistry Study Group

Join now

Related questions

146. Find the solubility of Cul in 0.40 M HCN solution. The Ksp of Cul is 1.1 x 10-12 and the K for the Cu(CN)2 complex ion is 1 X 1024

The solubility product for CuI(s) is 1.1 x 10^-2. Calculate the value of for the half-reaction .

orangemosquito128

The concentrations of NaCl and KI are at 0.160M and 0.120M respectively, in the following electrochemical cell: Cu(s) | CuI(s) | I-(aq) || Cl-(aq) | AgCl(s) | Ag(s) a) using the following half-reactions, calculate cell voltage: CuI(s) + e- <--> Cu(s) + I- Eo = -0.185V AgCl(s) + e- <--> Ag(s) + Cl- Eo = 0.222V

b) now calculate the cell voltage using the following half-reactions. The Ksp for AgCl and CuI are 1.8E-10 and 1.0E-12 respectively. Cu+ + e- <--> Cu(s) Eo = 0.518V Ag+ + e- <--> Ag(s) Eo = 0.7993V

Weekly leaderboard

Home

Homework Help 3,900,000

Chemistry 830,000

Find the solubility of CuI in .29M HCN solution. The ksp of CuI is 1.1 x 10^-12 and the kf for Cu(Cn)2 complex ion is 1 x 10^24. Please help.

Unlock all answers

Related textbook solutions

Basic Chemistry

Principles of Chemistry Molecular Approach

Chemistry: Structure and Properties

Principles of Chemistry Molecular Approach

Chemistry: A Molecular Approach

Chemistry: A Molecular Approach

Principles of Chemistry: A Molecular Approach

Chemistry: The Central Science

Related questions

Weekly leaderboard