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11 Dec 2019

Ka of benzoic acid ( HC7H5O2) = 6.5 x 10^-5 . 0.288 g of sodium benzoate (NaC7H5O2 , Mw = 144) is added 10.0 mL of a 0.0500 M HCl solution. Find the pH of the resultant solution.

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Tod Thiel
Tod ThielLv2
13 Dec 2019

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