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11 Dec 2019

Given the following equation: 2NH3(g) + 3CuO(s) ---> N2(g) +3Cu(s) + 3H2O(g) If 27.5g of NH3 is reacted with 35.7g of CuO, whatis the theoretical yield of Cu that is produced?

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Deanna Hettinger
Deanna HettingerLv2
13 Dec 2019

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Related questions

5. For the following reaction %u0394H is %u2013294 kJ. Usetabulated values of So to find Sorxn and determine if the reactionis spontaneous at 900oC.(2 pts). 2NH3(g) + 3CuO(s) %u2192 3H2O(l) +N2(g) + 3Cu(s)


step by step please :)


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For each of the following reactions:

a) Write the oxidation number for each element above the element. b) Identify the atom being oxidized and reduced. C) Identify the oxidizing reactant and reducing reactant.

a. 3CuO(aq) + 2NH3 (aq) ---> 3Cu (s) + N2 (g) + 3H2O (l)

Oxidized: Reduced: Oxi. Reactant: Red. Reactant:

b. Mg (s) + 2HCl (aq) ----> Mg+2(aq) + 2Cl-1 (aq) + H2 (g)

Oxidized: Reduced: Oxi. Reactant: Red. Reactant:

Part A

Weight of evaporating dish and watch glass

48.23 g

Weight of evaporating dish and watch glass and NaHCO3(s)

49.98 g

Actual weight of NaHCO3(s) reacted

1.75 g

Weight of evaporating dish and watch glass and NaCl(s)

49.11 g

Actual weight of NaCl(s) produced

0.88 g

Actual moles of NaHCO3(s) reacted

mol

Actual moles of NaCl(s) produced

mol

Theoretical weight of NaCl(s) produced

g

Theoretical moles of NaCl(s) produced

mol

% Yield

%

Part B

Weight of evaporating dish

36.89 g

Weight of evaporating dish and CuCO3*Cu(OH)2

39.33 g

Actual weight of CuCO3*Cu(OH)2 reacted

2.44 g

Weight of evaporating dish and watch glass and CuO(s)

38.83 g

Actual weight of CuO(s) produced

1.49 g

Actual moles of CuCO3*Cu(OH)2(s) reacted

mol

Actual moles of CuO(s) produced

mol

Theoretical weight of CuO(s) produced

g

Theoretical moles of CuO(s) produced

mol

% Yield

%

I have to balance the equations of two reactants: CuCO3*Cu(OH)2

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