Calculate the pH of a solution that's 1.00 M benzoic acid and 1.33 M sodium benzoate. The Ka of benzoic acid is 6.5 x 10-5.
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Your TA asks you to make 100 mL of a benzoic acid/benzoate buffer solution of pH = 3.84. The Ka of benzoic acid is 6.5 Ã 10â5 .
a) Determine the volumes of 0.50 M benzoic acid and 0.50 M sodium benzoate required to make 100.0 mL of a pH 3.84 buffer solution.
b) Determine the volumes of 0.50 M benzoic acid and 0.50 M sodium hydroxide required to make 100.0 mL of a pH 3.84 buffer solution.
A buffer is made containing equal concentrations of benzoic acid and sodium benzoate (the salt of the conjugate base for benzoic acid). The Ka value for benzoic acid is 6.5 x 10â5.
Calculate the pH of the solution to two decimal places.